Prove rightarrow sin (90^{o}-theta)cos (90^{o}-theta)=dfrac {tan
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Click here👆to get an answer to your question ✍️ Prove rightarrow sin -90-o-theta-cos -90-o-theta-dfrac -tan theta-1-tan -2-theta-
Prove sin-90-x2212-x3B8-cos-90-x2212-x3B8-tan-x3B8-1-tan2-x3B8-LHS-sin-90-x2212-x3B8-cos-90-x2212-x3B8-cos-x3B8-sin-x3B8-12-2sin-x3B8-cos-x3B8-12sin2-x3B8-12-2tan-x3B8-1-tan2-x3B8-tan-x3B8-1-tan2-x3B8-RHS
Simplify:dfrac {sin theta.csc (90-theta).tan theta}{csc (90-theta).cos theta.cot (90-theta)}
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sin(90-theta)* cos(90-theta) = tan theta/ 1+ tan^2 theta
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Find the value of $\sec \left( 90-\theta \right)=$ A) $\ cos ec\theta $ B) $\sin \theta $ C) $\cos \theta $ D) $\text{None of these}$
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सिद्ध कीजिए: ( cot ( 90^(@) - theta))/( tan theta ) + ( cosec ( 90^(@) - theta ). sin theta ) /(