trigonometry - $\tan(x)=\cot(90^\circ-x)$?? - Mathematics Stack

I was looking at a mark scheme for a question I was stuck on, and I came across this. You are asked to work out the value of $\tan 75^\circ$ after you've worked out $\cos 15^\circ$ and $\sin 15^\ci

tan(90-x)=cot(x) - Trigonometry

x) value of cot(90 – A)

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