∆ ABC is isosceles with AB = AC = 7.5 cm, and BC = 9 cm (in

∆ ABC is isosceles with AB = AC = 7.5 cm, and BC = 9 cm (in Figure). The height AD from A to BC, is 6 cm. Find the area of ∆ ABC. What will be the height from C to AB i.e., CE?

triangle {ABC} is isosceles with AB=AC=7.5cm and BC=9 cm(Fig.11.26

NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area

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ABC is an isosceles triangle with ab is equal to AC is equal to

DeltaABC is isosceles with AB=AC=7.5cm and BC=9cm. The height AD from

ABC is an isosceles triangle with AC = BC. If `A B^2=2A C^2

Ex 9.1, 8 - ABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm

triangle ABC is isosceles with AB equals to AC equal to 7.5 cm and

In the figure, given below, ABC is an isosceles triangle with BC